The difference between the lower class limits of adjacent classes provides the
a Suppose the growth chart at a pediatrician's office is not hung correctly such that it measures children two inches taller than their actual height. If the heights of 10 children are recorded, which of the following is a true statement?
McDonalds | Luppi's | Mellow Mushroom |
Friday's | McDonalds | McDonalds |
Pizza Hut | Taco Bell | McDonalds |
Mellow Mushroom | Luppi's | Pizza Hut |
McDonalds | Friday's | McDonalds |
Which of the following is the correct percent frequency for McDonalds?
McDonalds | Luppi's | Mellow Mushroom |
Friday's | McDonalds | McDonalds |
Pizza Hut | Taco Bell | McDonalds |
Mellow Mushroom | Luppi's | Pizza Hut |
McDonalds | Friday's | McDonalds |
Which of the following is the correct relative frequency for McDonalds?
Number of hours | Frequency |
0 - 9 | 20 |
10 - 19 | 80 |
20 - 29 | 200 |
30 - 39 | 100 |
The class width used in this frequency distribution is
Standard deviation = 8
Coefficient of variation = 64%
The mean would then be
Day | Stock Price |
1 | 84 |
2 | 87 |
3 | 84 |
4 | 88 |
5 | 85 |
6 | 90 |
7 | 91 |
The variance is
5 | 12 | 6 | 8 | 5 |
6 | 7 | 5 | 12 | 4 |
The 75th percentile is
Consider the following graphical summary.
This is an example of a _____.
Undergraduate Major | ||||
Graduate School | Business | Engineering | Others | Total |
Yes | 70 | 84 | 126 | 280 |
No | 182 | 208 | 130 | 520 |
Total | 252 | 292 | 256 | 800 |
Of those students who are planning on going to graduate school, what percentage are majoring in engineering?
Using the following data set of monthly rainfall amounts recorded for 10 randomly selected months in a two-year period, what is the five-number summary?
Sample data (in inches): 2, 8, 5, 0, 1, 5, 7, 5, 2, .5
McDonalds | Luppi's | Mellow Mushroom |
Friday's | McDonalds | McDonalds |
Pizza Hut | Taco Bell | McDonalds |
Mellow Mushroom | Luppi's | Pizza Hut |
McDonalds | Friday's | McDonalds |
Which of the following is the correct frequency distribution?
Number of hours | Frequency |
0 -9 | 20 |
10 - 19 | 80 |
20 - 29 | 200 |
30 - 39 | 100 |
The relative frequency of students working 10 - 19 hours per week is
Information on the number of new teachers hired in a school district for each of four years is given in the table below.
The percent frequency of new hires in 2019 is _____.
mean = 70 | range = 20 |
mode = 73 | variance = 784 |
median = 74 |
The coefficient of variation equals
Undergraduate Major | ||||
Graduate School | Business | Engineering | Others | Total |
Yes | 70 | 84 | 126 | 280 |
No | 182 | 208 | 130 | 520 |
Total | 252 | 292 | 256 | 800 |
The above crosstabulation shows
mean = 160 | range = 60 |
mode = 165 | variance = 324 |
median = 170 |
The coefficient of variation equals
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
A survey of 400 college seniors resulted in the following crosstabulation regarding their undergraduate major and whether or not they plan to go to graduate school.
What percentage of the undergraduates surveyed are majoring in Engineering?
Information on the number of new teachers hired in a school district for each of four years is given in the table below.
The percent frequency of new hires in 2019 is _____.
Number of hours | Frequency |
0 -9 | 20 |
10 - 19 | 80 |
20 - 29 | 200 |
30 - 39 | 100 |
The cumulative percent frequency for students working less than 20 hours per week is
Number of hours | Frequency |
0 -9 | 20 |
10 - 19 | 80 |
20 - 29 | 200 |
30 - 39 | 100 |
The relative frequency of students working 10 - 19 hours per week is
mean = 160 | range = 60 |
mode = 165 | variance = 324 |
median = 170 |
The coefficient of variation equals
mean = 160 | range = 60 |
mode = 165 | variance = 324 |
median = 170 |
The coefficient of variation equals
The table above is an example of _____ data.
Consider the following data summary.
This is an example of a _____.
Day | Stock Price |
1 | 84 |
2 | 87 |
3 | 84 |
4 | 88 |
5 | 85 |
6 | 90 |
7 | 91 |
The median is
mean = 160 | range = 60 |
mode = 165 | variance = 324 |
median = 170 |
The coefficient of variation equals
Day | Stock Price |
1 | 84 |
2 | 87 |
3 | 84 |
4 | 88 |
5 | 85 |
6 | 90 |
7 | 91 |
The mode is
Day | Stock Price |
1 | 84 |
2 | 87 |
3 | 84 |
4 | 88 |
5 | 85 |
6 | 90 |
7 | 91 |
The mode is
Consider the scatter diagram below.
What type of relationship is shown for the number of students and their average score?
Suppose a sample of 150 individuals was taken. Their gender and their preferred computer manufacturer was noted. Partial results of the study follow in a crosstabulation of column percentages.
If 80 of those in the study prefer Apple computers, how many males preferred Apple computers?
Number of hours | Frequency |
0 -9 | 20 |
10 - 19 | 80 |
20 - 29 | 200 |
30 - 39 | 100 |
The relative frequency of students working 10 - 19 hours per week is
Number of hours | Frequency |
0 -9 | 20 |
10 - 19 | 80 |
20 - 29 | 200 |
30 - 39 | 100 |
The cumulative percent frequency for students working less than 20 hours per week is
Number of hours | Frequency |
0 -9 | 20 |
10 - 19 | 80 |
20 - 29 | 200 |
30 - 39 | 100 |
The cumulative percent frequency for students working less than 20 hours per week is
Information on the number of new teachers hired in a school district for each of four years is given in the table below.
The percent frequency of new hires in 2019 is _____.
Undergraduate Major | ||||
Graduate School | Business | Engineering | Others | Total |
Yes | 70 | 84 | 126 | 280 |
No | 182 | 208 | 130 | 520 |
Total | 252 | 292 | 256 | 800 |
Of those students who are majoring in business, what percentage plans to go to graduate school?
Number of hours | Frequency |
0 - 9 | 20 |
10 - 19 | 80 |
20 - 29 | 200 |
30 - 39 | 100 |
The percentage of students who work at least 10 hours per week is
Day | Stock Price |
1 | 84 |
2 | 87 |
3 | 84 |
4 | 88 |
5 | 85 |
6 | 90 |
7 | 91 |
The median is
Undergraduate Major | ||||
Graduate School | Business | Engineering | Others | Total |
Yes | 70 | 84 | 126 | 280 |
No | 182 | 208 | 130 | 520 |
Total | 252 | 292 | 256 | 800 |
Of those students who are majoring in business, what percentage plans to go to graduate school?
Consider the scatter diagram below.
What type of relationship is shown for the number of students and their average score?
Number of hours | Frequency |
0 - 9 | 20 |
10 - 19 | 80 |
20 - 29 | 200 |
30 - 39 | 100 |
The class width used in this frequency distribution is
McDonalds | Luppi's | Mellow Mushroom |
Friday's | McDonalds | McDonalds |
Pizza Hut | Taco Bell | McDonalds |
Mellow Mushroom | Luppi's | Pizza Hut |
McDonalds | Friday's | McDonalds |
Which of the following distributions would be inappropriate for this data?
McDonalds | Luppi's | Mellow Mushroom |
Friday's | McDonalds | McDonalds |
Pizza Hut | Taco Bell | McDonalds |
Mellow Mushroom | Luppi's | Pizza Hut |
McDonalds | Friday's | McDonalds |
Which of the following displays is most appropriate for this data?
Undergraduate Major | ||||
Graduate School | Business | Engineering | Others | Total |
Yes | 70 | 84 | 126 | 280 |
No | 182 | 208 | 130 | 520 |
Total | 252 | 292 | 256 | 800 |
The above crosstabulation shows
What can be concluded from the scatter diagram below for the two variables, years of education and unemployment rate?
Number of hours | Frequency |
0 -9 | 20 |
10 - 19 | 80 |
20 - 29 | 200 |
30 - 39 | 100 |
The cumulative percent frequency for students working less than 20 hours per week is
McDonalds | Luppi's | Mellow Mushroom |
Friday's | McDonalds | McDonalds |
Pizza Hut | Taco Bell | McDonalds |
Mellow Mushroom | Luppi's | Pizza Hut |
McDonalds | Friday's | McDonalds |
Which of the following is the correct relative frequency for McDonalds?
Day | Stock Price |
1 | 84 |
2 | 87 |
3 | 84 |
4 | 88 |
5 | 85 |
6 | 90 |
7 | 91 |
The mode is
Undergraduate Major | ||||
Graduate School | Business | Engineering | Others | Total |
Yes | 70 | 84 | 126 | 280 |
No | 182 | 208 | 130 | 520 |
Total | 252 | 292 | 256 | 800 |
Of those students who are majoring in business, what percentage plans to go to graduate school?
McDonalds | Luppi's | Mellow Mushroom |
Friday's | McDonalds | McDonalds |
Pizza Hut | Taco Bell | McDonalds |
Mellow Mushroom | Luppi's | Pizza Hut |
McDonalds | Friday's | McDonalds |
Which of the following is the correct frequency distribution?
McDonalds | Luppi's | Mellow Mushroom |
Friday's | McDonalds | McDonalds |
Pizza Hut | Taco Bell | McDonalds |
Mellow Mushroom | Luppi's | Pizza Hut |
McDonalds | Friday's | McDonalds |
Which of the following is the correct percent frequency for McDonalds?
The number of sick days taken (per month) by 150 factory workers is summarized below.
The cumulative frequency for the class 11–15 is _____.
mean = 160 | range = 60 |
mode = 165 | variance = 324 |
median = 170 |
The coefficient of variation equals
McDonalds | Luppi's | Mellow Mushroom |
Friday's | McDonalds | McDonalds |
Pizza Hut | Taco Bell | McDonalds |
Mellow Mushroom | Luppi's | Pizza Hut |
McDonalds | Friday's | McDonalds |
Which of the following is the correct relative frequency for McDonalds?
Number of hours | Frequency |
0 - 9 | 20 |
10 - 19 | 80 |
20 - 29 | 200 |
30 - 39 | 100 |
The percentage of students who work at least 10 hours per week is
Undergraduate Major | ||||
Graduate School | Business | Engineering | Others | Total |
Yes | 70 | 84 | 126 | 280 |
No | 182 | 208 | 130 | 520 |
Total | 252 | 292 | 256 | 800 |
The above crosstabulation shows
Undergraduate Major | ||||
Graduate School | Business | Engineering | Others | Total |
Yes | 70 | 84 | 126 | 280 |
No | 182 | 208 | 130 | 520 |
Total | 252 | 292 | 256 | 800 |
Of those students who are majoring in business, what percentage plans to go to graduate school?
Day | Stock Price |
1 | 84 |
2 | 87 |
3 | 84 |
4 | 88 |
5 | 85 |
6 | 90 |
7 | 91 |
The mode is
Day | Stock Price |
1 | 84 |
2 | 87 |
3 | 84 |
4 | 88 |
5 | 85 |
6 | 90 |
7 | 91 |
The mode is
Day | Stock Price |
1 | 84 |
2 | 87 |
3 | 84 |
4 | 88 |
5 | 85 |
6 | 90 |
7 | 91 |
The mode is
Day | Stock Price |
1 | 84 |
2 | 87 |
3 | 84 |
4 | 88 |
5 | 85 |
6 | 90 |
7 | 91 |
The mode is
Day | Stock Price |
1 | 84 |
2 | 87 |
3 | 84 |
4 | 88 |
5 | 85 |
6 | 90 |
7 | 91 |
The mode is
Day | Stock Price |
1 | 84 |
2 | 87 |
3 | 84 |
4 | 88 |
5 | 85 |
6 | 90 |
7 | 91 |
The mode is
Undergraduate Major | ||||
Graduate School | Business | Engineering | Others | Total |
Yes | 70 | 84 | 126 | 280 |
No | 182 | 208 | 130 | 520 |
Total | 252 | 292 | 256 | 800 |
Of those students who are planning on going to graduate school, what percentage are majoring in engineering?
Number of hours | Frequency |
0 -9 | 20 |
10 - 19 | 80 |
20 - 29 | 200 |
30 - 39 | 100 |
The cumulative percent frequency for students working less than 20 hours per week is
McDonalds | Luppi's | Mellow Mushroom |
Friday's | McDonalds | McDonalds |
Pizza Hut | Taco Bell | McDonalds |
Mellow Mushroom | Luppi's | Pizza Hut |
McDonalds | Friday's | McDonalds |
Which of the following displays is most appropriate for this data?
Consider the following data as well as the corresponding stem-and-leaf display on the annual property taxes for eight residents of a city.
What is the leaf unit for the display?
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
The number of miles from their residence to their place of work for 120 employees is shown below.
The relative frequency of employees who drive 10 miles or less to work is _____.
Ŷ = 7 - 3x1 + 5x2
For this model, SSR = 3500, SSE = 1500, and the sample size is 18. The adjusted multiple coefficient of determination for this problem is
Ŷ = 30 + .7x1 + 3x2
Also provided are SST = 1200 and SSE = 384. The multiple coefficient of determination is
Ŷ = 30 + .7x1 + 3x2
Also provided are SST = 1200 and SSE = 384. At the 5% level, the model


Ŷ = 17 + 4x1 - 3x2 + 8x3 + 8x4
For this model, SSR = 700 and SSE = 100. The computed F statistic for testing the significance of the above model is
Coefficients | Standard Error | |||
Constant | 12.924 | 4.425 | ||
x1 | -3.682 | 2.630 | ||
x2 | 45.216 | 12.560 | ||
Analysis of Variance | ||||
Source ofVariation | Degrees of Freedom | Sum ofSquares | MeanSquare | F |
Regression | 4853 | 2426.5 | ||
Error | 485.3 |
Carry out the test of significance for the parameter β1 at the 1% level. The null hypothesis should
Ŷ = 30 + .7x1 + 3x2
Also provided are SST = 1200 and SSE = 384. The estimated income (in $) of a 30-year-old male is
| |||
Ŷ = 29 + 18x1 + 43x2 + 87x3
For this model, SSR = 600 and SSE = 400. The computed F statistic for testing the significance of the above model is
Ŷ = 17 + 4x1 - 3x2 + 8x3 + 8x4
For this model, SSR = 700 and SSE = 100. At the 5% level,
Coefficients | Standard Error | |||
Constant | 12.924 | 4.425 | ||
x1 | -3.682 | 2.630 | ||
x2 | 45.216 | 12.560 | ||
Analysis of Variance | ||||
Source of Variation | Degrees of Freedom | Sum of Squares | Mean Square | F |
Regression | 4853 | 2426.5 | ||
Error | 485.3 |
The F value obtained from the table which is used to test if there is a relationship among the variables at the 5% level equals
Ŷ = 30 + .7x1 + 3x2
Also provided are SST = 1200 and SSE = 384. The test statistic for testing the significance of the model is
Ŷ = 30 + .7x1 + 3x2
Also provided are SST = 1200 and SSE = 384. At the 5% level, the model
Ŷ = 7 - 3x1 + 5x2
For this model, SSR = 3500, SSE = 1500, and the sample size is 18. The coefficient of x2 indicates that if television advertisement is increased by $1 (holding the unit price constant), sales are expected to

Ŷ = 30 + .7x1 + 3x2
Also provided are SST = 1200 and SSE = 384. The yearly income (in $) expected of a 24-year-old male individual is
Ŷ = 30 + .7x1 + 3x2
Also provided are SST = 1200 and SSE = 384. The yearly income (in $) expected of a 24-year-old female individual is
Coefficients | Standard Error | |||
Constant | 12.924 | 4.425 | ||
x1 | -3.682 | 2.630 | ||
x2 | 45.216 | 12.560 | ||
Analysis of Variance | ||||
Source of Variation | Degrees of Freedom | Sum of Squares | Mean Square | F |
Regression | 4853 | 2426.5 | ||
Error | 485.3 |
The degrees of freedom for the sum of squares explained by the regression (SSR) are

Ŷ = 10 - 18x1 + 3x2 + 14x3
Also, the following standard errors and the sum of squares were obtained.
sb1 = 3 | sb2 = 6 | sb3 = 7 |
SST = 4800 | SSE = 1296 |
If you want to determine whether or not the coefficients of the independent variables are significant, the critical t value at α = .05 is
Ŷ = 10 - 18x1 + 3x2 + 14x3
Also, the following standard errors and the sum of squares were obtained.
sb1 = 3 | sb2 = 6 | sb3 = 7 |
SST = 4800 | SSE = 1296 |
The p-value for testing the significance of the regression model is
y = β0 + β1x1 + β2x12 + ε
is known as a
Consider the sample correlation coefficients in the table below.
How much of the variability in time can be explained by boxes?
Ŷ = 10 - 18x1 + 3x2 + 14x3
Also, the following standard errors and the sum of squares were obtained.
sb1 = 3 | sb2 = 6 | sb3 = 7 |
SST = 4800 | SSE = 1296 |
If we are interested in testing for the significance of the relationship among the variables (i.e., significance of the model), the critical value of F at α = .05 is
Ŷ = 30 + .7x1 + 3x2
Also provided are SST = 1200 and SSE = 384. At the 5% level, the model
Ŷ = 30 + .7x1 + 3x2
Also provided are SST = 1200 and SSE = 384. If we want to test for the significance of the model, the critical value of F at α = .05 is
Coefficients | Standard Error | |||
Constant | 12.924 | 4.425 | ||
x1 | -3.682 | 2.630 | ||
x2 | 45.216 | 12.560 | ||
Analysis of Variance | ||||
Source ofVariation | Degrees of Freedom | Sum ofSquares | MeanSquare | F |
Regression | 4853 | 2426.5 | ||
Error | 485.3 |
Carry out the test of significance for the parameter β1 at the 1% level. The null hypothesis should
Ŷ = 30 + .7x1 + 3x2
Also provided are SST = 1200 and SSE = 384. The test statistic for testing the significance of the model is
SSR = 165 |
SSE = 60 |
If we want to test for the significance of the model at a .05 level of significance, the critical F value (from the table) is
Consider the sample correlation coefficients in the table below.
How much of the variability in time can be explained by boxes?
Ŷ = 10 - 18x1 + 3x2 + 14x3
Also, the following standard errors and the sum of squares were obtained.
sb1 = 3 | sb2 = 6 | sb3 = 7 |
SST = 4800 | SSE = 1296 |
The test statistic for testing the significance of the model is
y = β0 + β1x1 + β2x12 + ε
is known as a
Ŷ = 10 - 18x1 + 3x2 + 14x3
Also, the following standard errors and the sum of squares were obtained.
sb1 = 3 | sb2 = 6 | sb3 = 7 |
SST = 4800 | SSE = 1296 |
The multiple coefficient of determination is
Ŷ = 10 - 18x1 + 3x2 + 14x3
Also, the following standard errors and the sum of squares were obtained.
sb1 = 3 | sb2 = 6 | sb3= 7 |
SST = 4800 | SSE = 1296 |
At the 5% level, the coefficient of x2
Ŷ = 7 - 3x1 + 5x2
For this model, SSR = 3500, SSE = 1500, and the sample size is 18. The adjusted multiple coefficient of determination for this problem is
Ŷ = 30 + .7x1 + 3x2
Also provided are SST = 1200 and SSE = 384. If we want to test for the significance of the model, the critical value of F at α = .05 is
SSR = 165 |
SSE = 60 |
If we want to test for the significance of the model at a .05 level of significance, the critical F value (from the table) is
Ŷ = 29 + 18x1 + 43x2 + 87x3
For this model, SSR = 600 and SSE = 400. The computed F statistic for testing the significance of the above model is
Coefficients | Standard Error | |||
Constant | 12.924 | 4.425 | ||
x1 | -3.682 | 2.630 | ||
x2 | 45.216 | 12.560 | ||
Analysis of Variance | ||||
Source of Variation | Degrees of Freedom | Sum of Squares | Mean Square | F |
Regression | 4853 | 2426.5 | ||
Error | 485.3 |
Carry out the test to determine if there is a relationship among the variables at the 5% level. The null hypothesis should


Ŷ = 7 - 3x1 + 5x2
For this model, SSR = 3500, SSE = 1500, and the sample size is 18. The multiple coefficient of determination for this problem is
Coefficients | Standard Error | |||
Constant | 12.924 | 4.425 | ||
x1 | -3.682 | 2.630 | ||
x2 | 45.216 | 12.560 | ||
Analysis of Variance | ||||
Source of Variation | Degrees of Freedom | Sum of Squares | Mean Square | F |
Regression | 4853 | 2426.5 | ||
Error | 485.3 |
The interpretation of the coefficient of x1 is that
Ŷ = 30 + .7x1 + 3x2
Also provided are SST = 1200 and SSE = 384. If we want to test for the significance of the model, the critical value of F at α = .05 is
SSR = 165 |
SSE = 60 |
The test statistic obtained from the information provided is


Ŷ = 30 + .7x1 + 3x2
Also provided are SST = 1200 and SSE = 384. If we want to test for the significance of the model, the critical value of F at α = .05 is
Coefficients | Standard Error | |||
Constant | 12.924 | 4.425 | ||
x1 | -3.682 | 2.630 | ||
x2 | 45.216 | 12.560 | ||
Analysis of Variance | ||||
Source of Variation | Degrees of Freedom | Sum of Squares | Mean Square | F |
Regression | 4853 | 2426.5 | ||
Error | 485.3 |
The interpretation of the coefficient of x1 is that
Ŷ = 17 + 4x1 - 3x2 + 8x3 + 8x4
For this model, SSR = 700 and SSE = 100. The computed F statistic for testing the significance of the above model is
Ŷ = 10 - 18x1 + 3x2 + 14x3
Also, the following standard errors and the sum of squares were obtained.
sb1 = 3 | sb2 = 6 | sb3= 7 |
SST = 4800 | SSE = 1296 |
At the 5% level, the coefficient of x2

Ŷ = 10 - 18x1 + 3x2 + 14x3
Also, the following standard errors and the sum of squares were obtained.
sb1 = 3 | sb2 = 6 | sb3 = 7 |
SST = 4800 | SSE = 1296 |
If we are interested in testing for the significance of the relationship among the variables (i.e., significance of the model), the critical value of F at α = .05 is
Ŷ = 10 - 18x1 + 3x2 + 14x3
Also, the following standard errors and the sum of squares were obtained.
sb1 = 3 | sb2 = 6 | sb3 = 7 |
SST = 4800 | SSE = 1296 |
At the 5% level, the coefficient of x1
Ŷ = 10 - 18x1 + 3x2 + 14x3
Also, the following standard errors and the sum of squares were obtained.
sb1 = 3 | sb2 = 6 | sb3 = 7 |
SST = 4800 | SSE = 1296 |
The test statistic for testing the significance of the model is
Ŷ = 10 - 18x1 + 3x2 + 14x3
Also, the following standard errors and the sum of squares were obtained.
sb1 = 3 | sb2 = 6 | sb3 = 7 |
SST = 4800 | SSE = 1296 |
If you want to determine whether or not the coefficients of the independent variables are significant, the critical t value at α = .05 is
Ŷ = 7 + 2x1 + 9x2
As x1 increases by 1 unit (holding x2 constant), y is expected to
Ŷ = 17 + 4x1 - 3x2 + 8x3 + 8x4
For this model, SSR = 700 and SSE = 100. The multiple coefficient of determination for the above model is
Coefficients | Standard Error | |||
Constant | 12.924 | 4.425 | ||
x1 | -3.682 | 2.630 | ||
x2 | 45.216 | 12.560 | ||
Analysis of Variance | ||||
Source of Variation | Degrees of Freedom | Sum of Squares | Mean Square | F |
Regression | 4853 | 2426.5 | ||
Error | 485.3 |
The sum of squares due to error (SSE) equals

SSR = 165 |
SSE = 60 |
The multiple coefficient of determination is
Coefficients | Standard Error | |||
Constant | 12.924 | 4.425 | ||
x1 | -3.682 | 2.630 | ||
x2 | 45.216 | 12.560 | ||
Analysis of Variance | ||||
Source of Variation | Degrees of Freedom | Sum of Squares | Mean Square | F |
Regression | 4853 | 2426.5 | ||
Error | 485.3 |
We want to test whether the parameter β1 is significant. The test statistic equals
y = β0 + β1x1 + ε
is referred to as a
Ŷ = 10 - 18x1 + 3x2 + 14x3
Also, the following standard errors and the sum of squares were obtained.
sb1 = 3 | sb2 = 6 | sb3 = 7 |
SST = 4800 | SSE = 1296 |
The test statistic for testing the significance of the model is
Ŷ = 7 - 3x1 + 5x2
For this model, SSR = 3500, SSE = 1500, and the sample size is 18. To test for the significance of the model, the test statistic F is
Ŷ = 17 + 4x1 - 3x2 + 8x3 + 8x4
For this model, SSR = 700 and SSE = 100. The critical F value at α = .05 is
Ŷ = 10 - 18x1 + 3x2 + 14x3
Also, the following standard errors and the sum of squares were obtained.
sb1 = 3 | sb2 = 6 | sb3 = 7 |
SST = 4800 | SSE = 1296 |
At the .05 level of significance, the coefficient of x3
Coefficients | Standard Error | |||
Constant | 12.924 | 4.425 | ||
x1 | -3.682 | 2.630 | ||
x2 | 45.216 | 12.560 | ||
Analysis of Variance | ||||
Source of Variation | Degrees of Freedom | Sum of Squares | Mean Square | F |
Regression | 4853 | 2426.5 | ||
Error | 485.3 |
The t value obtained from the table which is used to test an individual parameter at the 1% level is
Consider the residual plot from the multiple regression analysis to determine the time required to load a truck given the number of boxes to be loaded and the average weight of the boxes.
How many data points in the residual plot given should be investigated further as potential outliers?
Consider the following hypothesis problem.
n = 30 | H0: σ2 = 500 |
s2 = 625 | Ha: σ2 ≠ 500 |
The test statistic equals
Sample A | Sample B | |
n | 11 | 10 |
s2 | 12.1 | 5 |
The test statistic for this problem equals
n = 23 | s2 = 60 | H0: σ2 ≤ 66 |
Ha: σ2 > 66 |
If the test is to be performed at the .05 level of significance, the null hypothesis
Consider the scenario where
The null hypothesis is to be tested at the 5% level of significance. The critical value(s) from the table is(are) _____.
Given the sample information below, what test statistic should be used to determine whether the standard deviations are equal for two populations, prior to performing a hypothesis test for the equality of the population means?
Sample A | Sample B | |
n | 24 | 16 |
s2 | 32 | 38 |
We want to test the hypothesis that the population variances are equal. The null hypothesis is to be tested at the 10% level of significance. The critical value from the F distribution table is
n = 14 | H0: σ2 ≤ 410 |
s = 20 | Ha: σ2 > 410 |
The test statistic equals
n = 23 | s2 = 60 | H0: σ2 ≤ 66 |
Ha: σ2 > 66 |
If the test is to be performed at the .05 level of significance, the null hypothesis
n = 30 | H0: σ2 = 500 |
s2 = 625 | Ha: σ2 ≠ 500 |
The test statistic equals
n = 30 | H0: σ2 = 500 |
s2 = 625 | Ha: σ2 ≠ 500 |
At the 5% level of significance, the null hypothesis
n = 23 | s2 = 60 | H0: σ2 ≤ 66 |
Ha: σ2 > 66 |
If the test is to be performed at the 5% level, the critical value(s) from the chi-square distribution table is(are)
2 | 3 | 5 | 5 | 7 | 8 | 8 | 9 | 9 | 10 |
11 | 11 | 12 | 12 | 12 | 12 | 13 | 13 | 13 | 14 |
15 | 15 | 15 | 16 | 16 | 17 | 17 | 18 | 18 | 19 |
The number of intervals or categories used to test the hypothesis for this problem is
2 | 3 | 5 | 5 | 7 | 8 | 8 | 9 | 9 | 10 |
11 | 11 | 12 | 12 | 12 | 12 | 13 | 13 | 13 | 14 |
15 | 15 | 15 | 16 | 16 | 17 | 17 | 18 | 18 | 19 |
The calculated value for the test statistic equals
Do you support capital punishment? | Number of individuals |
Yes | 40 |
No | 60 |
No Opinion | 50 |
We are interested in determining whether or not the opinions of the individuals (as to Yes, No, and No Opinion) are uniformly distributed. The conclusion of the test at the 5% level of significance is that the
Teens | Adults | Total | |
Coffee | 50 | 200 | 250 |
Tea | 100 | 150 | 250 |
Soft Drink | 200 | 200 | 400 |
Other | 50 | 50 | 100 |
400 | 600 | 1000 |
We are asked to test for independence between age (i.e., adult and teen) and drink preferences. The expected number of adults who prefer coffee is
Political Party | Support |
Democrats | 100 |
Republicans | 120 |
Independents | 80 |
We are interested in determining whether or not the opinions of the individuals of the three groups are uniformly distributed. The expected frequency for each group is
Freshmen | 83 |
Sophomores | 68 |
Juniors | 85 |
Seniors | 64 |
We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year. At a .05 level of significance, the null hypothesis
2 | 3 | 5 | 5 | 7 | 8 | 8 | 9 | 9 | 10 |
11 | 11 | 12 | 12 | 12 | 12 | 13 | 13 | 13 | 14 |
15 | 15 | 15 | 16 | 16 | 17 | 17 | 18 | 18 | 19 |
The calculated value for the test statistic equals
Teens | Adults | Total | |
Coffee | 50 | 200 | 250 |
Tea | 100 | 150 | 250 |
Soft Drink | 200 | 200 | 400 |
Other | 50 | 50 | 100 |
400 | 600 | 1000 |
We are asked to test for independence between age (i.e., adult and teen) and drink preferences. The test statistic for this test of independence is
Do you support capital punishment? | Number of individuals |
Yes | 40 |
No | 60 |
No Opinion | 50 |
We are interested in determining whether or not the opinions of the individuals (as to Yes, No, and No Opinion) are uniformly distributed. The conclusion of the test at the 5% level of significance is that the
Freshmen | 83 |
Sophomores | 68 |
Juniors | 85 |
Seniors | 64 |
We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year. The expected frequency of seniors is
Number of Cars Arriving in a 10-Minute Interval | Frequency |
0 | 3 |
1 | 10 |
2 | 15 |
3 | 23 |
4 | 30 |
5 | 24 |
6 | 20 |
7 | 13 |
8 | 8 |
9 or more | 4 |
150 |
The calculated value for the test statistic equals
Do you support capital punishment? | Number of individuals |
Yes | 40 |
No | 60 |
No Opinion | 50 |
We are interested in determining whether or not the opinions of the individuals (as to Yes, No, and No Opinion) are uniformly distributed. The conclusion of the test at the 5% level of significance is that the
Teens | Adults | Total | |
Coffee | 50 | 200 | 250 |
Tea | 100 | 150 | 250 |
Soft Drink | 200 | 200 | 400 |
Other | 50 | 50 | 100 |
400 | 600 | 1000 |
We are asked to test for independence between age (i.e., adult and teen) and drink preferences. The expected number of adults who prefer coffee is
2 | 3 | 5 | 5 | 7 | 8 | 8 | 9 | 9 | 10 |
11 | 11 | 12 | 12 | 12 | 12 | 13 | 13 | 13 | 14 |
15 | 15 | 15 | 16 | 16 | 17 | 17 | 18 | 18 | 19 |
The number of intervals or categories used to test the hypothesis for this problem is
Political Party | Support |
Democrats | 100 |
Republicans | 120 |
Independents | 80 |
We are interested in determining whether or not the opinions of the individuals of the three groups are uniformly distributed. The calculated value for the test statistic equals
Teens | Adults | Total | |
Coffee | 50 | 200 | 250 |
Tea | 100 | 150 | 250 |
Soft Drink | 200 | 200 | 400 |
Other | 50 | 50 | 100 |
400 | 600 | 1000 |
We are asked to test for independence between age (i.e., adult and teen) and drink preferences. The test statistic for this test of independence is
Political Party | Support |
Democrats | 100 |
Republicans | 120 |
Independents | 80 |
We are interested in determining whether or not the opinions of the individuals of the three groups are uniformly distributed. The number of degrees of freedom associated with this problem is
2 | 3 | 5 | 5 | 7 | 8 | 8 | 9 | 9 | 10 |
11 | 11 | 12 | 12 | 12 | 12 | 13 | 13 | 13 | 14 |
15 | 15 | 15 | 16 | 16 | 17 | 17 | 18 | 18 | 19 |
The calculated value for the test statistic equals
2 | 3 | 5 | 5 | 7 | 8 | 8 | 9 | 9 | 10 |
11 | 11 | 12 | 12 | 12 | 12 | 13 | 13 | 13 | 14 |
15 | 15 | 15 | 16 | 16 | 17 | 17 | 18 | 18 | 19 |
The number of intervals or categories used to test the hypothesis for this problem is
A researcher would like to test the hypothesis that population B has a smaller variance than population A, using a 5% level of significance for the hypothesis test. What is the critical value from the F distribution table?
n = 30 | H0: σ2 = 500 |
s2 = 625 | Ha: σ2 ≠ 500 |
The test statistic equals
Sample A | Sample B | |
n | 24 | 16 |
s2 | 32 | 38 |
We want to test the hypothesis that the population variances are equal. The test statistic for this problem equals
Given the sample information below, what test statistic should be used to determine whether the standard deviations are equal for two populations, prior to performing a hypothesis test for the equality of the population means?
n = 23 | s2 = 60 | H0: σ2 ≤ 66 |
Ha: σ2 > 66 |
The p-value is
n = 30 | H0: σ2 = 500 |
s2 = 625 | Ha: σ2 ≠ 500 |
The test statistic equals
n = 23 | s2 = 60 | H0: σ2 ≤ 66 |
Ha: σ2 > 66 |
The p-value is
Sample A | Sample B | |
n | 24 | 16 |
s2 | 32 | 38 |
We want to test the hypothesis that the population variances are equal. The test statistic for this problem equals
n = 14 | H0: σ2 ≤ 410 |
s = 20 | Ha: σ2 > 410 |
The null hypothesis is to be tested at the 5% level of significance. The critical value(s) from the chi-square distribution table is(are)
onsider the scenario where
The null hypothesis is to be tested at the 5% level of significance. The critical value(s) from the table is(are) _____.
Freshmen | 83 |
Sophomores | 68 |
Juniors | 85 |
Seniors | 64 |
We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year. The calculated value for the test statistic equals
Number of Cars Arriving in a 10-Minute Interval | Frequency |
0 | 3 |
1 | 10 |
2 | 15 |
3 | 23 |
4 | 30 |
5 | 24 |
6 | 20 |
7 | 13 |
8 | 8 |
9 or more | 4 |
150 |
Freshmen | 83 |
Sophomores | 68 |
Juniors | 85 |
Seniors | 64 |
We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year. The expected number of freshmen is
2 | 3 | 5 | 5 | 7 | 8 | 8 | 9 | 9 | 10 |
11 | 11 | 12 | 12 | 12 | 12 | 13 | 13 | 13 | 14 |
15 | 15 | 15 | 16 | 16 | 17 | 17 | 18 | 18 | 19 |
The calculated value for the test statistic equals
Political Party | Support |
Democrats | 100 |
Republicans | 120 |
Independents | 80 |
We are interested in determining whether or not the opinions of the individuals of the three groups are uniformly distributed. The expected frequency for each group is
Teens | Adults | Total | |
Coffee | 50 | 200 | 250 |
Tea | 100 | 150 | 250 |
Soft Drink | 200 | 200 | 400 |
Other | 50 | 50 | 100 |
400 | 600 | 1000 |
We are asked to test for independence between age (i.e., adult and teen) and drink preferences. With a .05 level of significance, the critical value for the test is
Freshmen | 83 |
Sophomores | 68 |
Juniors | 85 |
Seniors | 64 |
We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year. The expected number of freshmen is
2 | 3 | 5 | 5 | 7 | 8 | 8 | 9 | 9 | 10 |
11 | 11 | 12 | 12 | 12 | 12 | 13 | 13 | 13 | 14 |
15 | 15 | 15 | 16 | 16 | 17 | 17 | 18 | 18 | 19 |
The calculated value for the test statistic equals
Do you support capital punishment? | Number of individuals |
Yes | 40 |
No | 60 |
No Opinion | 50 |
We are interested in determining whether or not the opinions of the individuals (as to Yes, No, and No Opinion) are uniformly distributed. The expected frequency for each group is
Freshmen | 83 |
Sophomores | 68 |
Juniors | 85 |
Seniors | 64 |
We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year. At a .05 level of significance, the null hypothesis
Political Party | Support |
Democrats | 100 |
Republicans | 120 |
Independents | 80 |
We are interested in determining whether or not the opinions of the individuals of the three groups are uniformly distributed. The expected frequency for each group is
A random sample of 550 physicians was selected and classified according to the type of practice they operate and whether or not their practice was full (meaning, not accepting new patients). The counts are given in the table below.
The test statistic for a test of independence is χ2 = 34.893. What is the p-value for this test?
Political Party | Support |
Democrats | 100 |
Republicans | 120 |
Independents | 80 |
We are interested in determining whether or not the opinions of the individuals of the three groups are uniformly distributed. The expected frequency for each group is
Teens | Adults | Total | |
Coffee | 50 | 200 | 250 |
Tea | 100 | 150 | 250 |
Soft Drink | 200 | 200 | 400 |
Other | 50 | 50 | 100 |
400 | 600 | 1000 |
We are asked to test for independence between age (i.e., adult and teen) and drink preferences. The expected number of adults who prefer coffee is
Teens | Adults | Total | |
Coffee | 50 | 200 | 250 |
Tea | 100 | 150 | 250 |
Soft Drink | 200 | 200 | 400 |
Other | 50 | 50 | 100 |
400 | 600 | 1000 |
We are asked to test for independence between age (i.e., adult and teen) and drink preferences. The test statistic for this test of independence is
Number of Cars Arriving in a 10-Minute Interval | Frequency |
0 | 3 |
1 | 10 |
2 | 15 |
3 | 23 |
4 | 30 |
5 | 24 |
6 | 20 |
7 | 13 |
8 | 8 |
9 or more | 4 |
150 |
The calculated value for the test statistic equals
Number of Cars Arriving in a 10-Minute Interval | Frequency |
0 | 3 |
1 | 10 |
2 | 15 |
3 | 23 |
4 | 30 |
5 | 24 |
6 | 20 |
7 | 13 |
8 | 8 |
9 or more | 4 |
150 |
Do you support capital punishment? | Number of individuals |
Yes | 40 |
No | 60 |
No Opinion | 50 |
We are interested in determining whether or not the opinions of the individuals (as to Yes, No, and No Opinion) are uniformly distributed. The calculated value for the test statistic equals
Freshmen | 83 |
Sophomores | 68 |
Juniors | 85 |
Seniors | 64 |
We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year. The p-value is
2 | 3 | 5 | 5 | 7 | 8 | 8 | 9 | 9 | 10 |
11 | 11 | 12 | 12 | 12 | 12 | 13 | 13 | 13 | 14 |
15 | 15 | 15 | 16 | 16 | 17 | 17 | 18 | 18 | 19 |
At the 5% level of significance, the conclusion of the test is that the
Do you support capital punishment? | Number of individuals |
Yes | 40 |
No | 60 |
No Opinion | 50 |
We are interested in determining whether or not the opinions of the individuals (as to Yes, No, and No Opinion) are uniformly distributed. The expected frequency for each group is
A random sample of 100 high school students was surveyed regarding their favorite subject. The following counts were obtained:
The researcher conducted a test to determine whether the proportion of students was equal for all four subjects. What is the value of the test statistic?
Teens | Adults | Total | |
Coffee | 50 | 200 | 250 |
Tea | 100 | 150 | 250 |
Soft Drink | 200 | 200 | 400 |
Other | 50 | 50 | 100 |
400 | 600 | 1000 |
We are asked to test for independence between age (i.e., adult and teen) and drink preferences. With a .05 level of significance, the critical value for the test is
Do you support capital punishment? | Number of individuals |
Yes | 40 |
No | 60 |
No Opinion | 50 |
We are interested in determining whether or not the opinions of the individuals (as to Yes, No, and No Opinion) are uniformly distributed. The conclusion of the test at the 5% level of significance is that the
Number of Cars Arriving in a 10-Minute Interval | Frequency |
0 | 3 |
1 | 10 |
2 | 15 |
3 | 23 |
4 | 30 |
5 | 24 |
6 | 20 |
7 | 13 |
8 | 8 |
9 or more | 4 |
150 |
Given the sample information below, what test statistic should be used to determine whether the standard deviations are equal for two populations, prior to performing a hypothesis test for the equality of the population means?
n = 14 | H0: σ2 ≤ 410 |
s = 20 | Ha: σ2 > 410 |
At the 5% level of significance, the null hypothesis
Teens | Adults | Total | |
Coffee | 50 | 200 | 250 |
Tea | 100 | 150 | 250 |
Soft Drink | 200 | 200 | 400 |
Other | 50 | 50 | 100 |
400 | 600 | 1000 |
We are asked to test for independence between age (i.e., adult and teen) and drink preferences. The expected number of adults who prefer coffee is
Freshmen | 83 |
Sophomores | 68 |
Juniors | 85 |
Seniors | 64 |
We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year. The calculated value for the test statistic equals
Political Party | Support |
Democrats | 100 |
Republicans | 120 |
Independents | 80 |
We are interested in determining whether or not the opinions of the individuals of the three groups are uniformly distributed. The number of degrees of freedom associated with this problem is
Freshmen | 83 |
Sophomores | 68 |
Juniors | 85 |
Seniors | 64 |
We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year. The p-value is
Sample A | Sample B | |
n | 24 | 16 |
s2 | 32 | 38 |
We want to test the hypothesis that the population variances are equal. The null hypothesis is to be tested at the 10% level of significance. The critical value from the F distribution table is
Sample A | Sample B | |
n | 24 | 16 |
s2 | 32 | 38 |
We want to test the hypothesis that the population variances are equal. At the 10% level of significance, the null hypothesis
n = 14 | H0: σ2 ≤ 410 |
s = 20 | Ha: σ2 > 410 |
The null hypothesis is to be tested at the 5% level of significance. The critical value(s) from the chi-square distribution table is(are)
n = 14 | H0: σ2 ≤ 410 |
s = 20 | Ha: σ2 > 410 |
The null hypothesis is to be tested at the 5% level of significance. The critical value(s) from the chi-square distribution table is(are)
n = 14 | H0: σ2 ≤ 410 |
s = 20 | Ha: σ2 > 410 |
The null hypothesis is to be tested at the 5% level of significance. The critical value(s) from the chi-square distribution table is(are)
n = 30 | H0: σ2 = 500 |
s2 = 625 | Ha: σ2 ≠ 500 |
At the 5% level of significance, the null hypothesis
2 | 3 | 5 | 5 | 7 | 8 | 8 | 9 | 9 | 10 |
11 | 11 | 12 | 12 | 12 | 12 | 13 | 13 | 13 | 14 |
15 | 15 | 15 | 16 | 16 | 17 | 17 | 18 | 18 | 19 |
At the 5% level of significance, the conclusion of the test is that the
A random sample of 550 physicians was selected and classified according to the type of practice they operate and whether or not their practice was full (meaning, not accepting new patients). The counts are given in the table below.
The test statistic for a test of independence is χ2 = 34.893. What is the p-value for this test?
2 | 3 | 5 | 5 | 7 | 8 | 8 | 9 | 9 | 10 |
11 | 11 | 12 | 12 | 12 | 12 | 13 | 13 | 13 | 14 |
15 | 15 | 15 | 16 | 16 | 17 | 17 | 18 | 18 | 19 |
The calculated value for the test statistic equals
Number of Cars Arriving in a 10-Minute Interval | Frequency |
0 | 3 |
1 | 10 |
2 | 15 |
3 | 23 |
4 | 30 |
5 | 24 |
6 | 20 |
7 | 13 |
8 | 8 |
9 or more | 4 |
150 |
The calculated value for the test statistic equals
Teens | Adults | Total | |
Coffee | 50 | 200 | 250 |
Tea | 100 | 150 | 250 |
Soft Drink | 200 | 200 | 400 |
Other | 50 | 50 | 100 |
400 | 600 | 1000 |
We are asked to test for independence between age (i.e., adult and teen) and drink preferences. The expected number of adults who prefer coffee is
Teens | Adults | Total | |
Coffee | 50 | 200 | 250 |
Tea | 100 | 150 | 250 |
Soft Drink | 200 | 200 | 400 |
Other | 50 | 50 | 100 |
400 | 600 | 1000 |
We are asked to test for independence between age (i.e., adult and teen) and drink preferences. The expected number of adults who prefer coffee is
A random sample of 100 high school students was surveyed regarding their favorite subject. The following counts were obtained:
The researcher conducted a test to determine whether the proportion of students was equal for all four subjects. What is the value of the test statistic?
Freshmen | 83 |
Sophomores | 68 |
Juniors | 85 |
Seniors | 64 |
We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year. At a .05 level of significance, the null hypothesis
2 | 3 | 5 | 5 | 7 | 8 | 8 | 9 | 9 | 10 |
11 | 11 | 12 | 12 | 12 | 12 | 13 | 13 | 13 | 14 |
15 | 15 | 15 | 16 | 16 | 17 | 17 | 18 | 18 | 19 |
The number of intervals or categories used to test the hypothesis for this problem is
Political Party | Support |
Democrats | 100 |
Republicans | 120 |
Independents | 80 |
We are interested in determining whether or not the opinions of the individuals of the three groups are uniformly distributed. The calculated value for the test statistic equals
Political Party | Support |
Democrats | 100 |
Republicans | 120 |
Independents | 80 |
We are interested in determining whether or not the opinions of the individuals of the three groups are uniformly distributed. The expected frequency for each group is
Do you support capital punishment? | Number of individuals |
Yes | 40 |
No | 60 |
No Opinion | 50 |
We are interested in determining whether or not the opinions of the individuals (as to Yes, No, and No Opinion) are uniformly distributed. The conclusion of the test at the 5% level of significance is that the
Do you support capital punishment? | Number of individuals |
Yes | 40 |
No | 60 |
No Opinion | 50 |
We are interested in determining whether or not the opinions of the individuals (as to Yes, No, and No Opinion) are uniformly distributed. The p-value is
Do you support capital punishment? | Number of individuals |
Yes | 40 |
No | 60 |
No Opinion | 50 |
We are interested in determining whether or not the opinions of the individuals (as to Yes, No, and No Opinion) are uniformly distributed. The p-value is
Do you support capital punishment? | Number of individuals |
Yes | 40 |
No | 60 |
No Opinion | 50 |
We are interested in determining whether or not the opinions of the individuals (as to Yes, No, and No Opinion) are uniformly distributed. The p-value is
A random sample of 16 students selected from the student body of a large university had an average age of 25 years and a standard deviation of 2 years. We want to determine if the average age of all the students at the university is significantly more than 24. Assume the distribution of the population of ages is normal. The p-value is between
H0: μ ≥ 500
Ha: μ < 500
the null hypothesis will be rejected, if the p-value is
n = 49, x̄ = 50, s = 7
H0: μ ≥ 52
Ha: μ < 52
the test statistic is
H0: μ ≥ 150
Ha: μ < 150
the test statistic
H0: μ ≥ 500
Ha: μ < 500
the null hypothesis will be rejected, if the p-value is
H0: μ ≥ 500
Ha: μ < 500
the null hypothesis will be rejected, if the p-value is
Assume normally distributed populations with equal variances.
Sample 1 | Sample 2 | |
Sample Mean | 45 | 42 |
Sample Variance | 85 | 90 |
Sample Size | 10 | 12 |
The 95% confidence interval for the difference between the two population means is (use rounded standard error)
Individual | Method 1 | Method 2 |
1 | 7 | 5 |
2 | 5 | 9 |
3 | 6 | 8 |
4 | 7 | 7 |
5 | 5 | 6 |
The point estimate for the difference between the means of the two populations (Method 1 - Method 2) is
The following information was obtained from matched samples:
If the null hypothesis tested is H0: µd = 0, what is the test statistic for the difference between the two population means?
Product | Shoppers Surveyed | Shoppers Favoring This Product |
A | 800 | 560 |
B | 900 | 612 |
The 95% confidence interval estimate for the difference between the populations favoring the products is
Today | Five Years Ago | |
x̄ | 82 | 88 |
σ2 | 112.5 | 54 |
n | 45 | 36 |
The 95% confidence interval for the difference between the two population means is
Store's Card | Major Credit Card | |
Sample size | 64 | 49 |
Sample mean | $140 | $125 |
Population standard deviation | $10 | $8 |
A 95% confidence interval estimate for the difference between the average purchases of all customers using the two different credit cards is
Production output (i.e., number of parts) for a random sample of days from two different plants is shown below.
What is the estimate of the standard deviation for the difference between the two means?
Today | Five Years Ago | |
x̄ | 82 | 88 |
σ2 | 112.5 | 54 |
n | 45 | 36 |
The standard error of x̄1 - x̄2 is
Individual | Method 1 | Method 2 |
1 | 7 | 5 |
2 | 5 | 9 |
3 | 6 | 8 |
4 | 7 | 7 |
5 | 5 | 6 |
The point estimate for the difference between the means of the two populations (Method 1 - Method 2) is
Individual | Method 1 | Method 2 |
1 | 7 | 5 |
2 | 5 | 9 |
3 | 6 | 8 |
4 | 7 | 7 |
5 | 5 | 6 |
The 95% confidence interval for the difference between the two population means is
Under Age of 18 | Over Age of 18 |
n1 = 500 | n2 = 600 |
Number of accidents = 180 | Number of accidents = 150 |
We are interested in determining if the accident proportions differ between the two age groups. The pooled estimator of the population proportion is
Assume normally distributed populations with equal variances.
Sample 1 | Sample 2 | |
Sample Mean | 45 | 42 |
Sample Variance | 85 | 90 |
Sample Size | 10 | 12 |
The 95% confidence interval for the difference between the two population means is (use rounded standard error)
Assume normally distributed populations with equal variances.
Sample 1 | Sample 2 | |
Sample Mean | 45 | 42 |
Sample Variance | 85 | 90 |
Sample Size | 10 | 12 |
The degrees of freedom for the t distribution are
Today | Five Years Ago | |
x̄ | 82 | 88 |
σ2 | 112.5 | 54 |
n | 45 | 36 |
The test statistic for the difference between the two population means is
Driver | Manufacturer A | Manufacturer B |
1 | 32 | 28 |
2 | 27 | 22 |
3 | 26 | 27 |
4 | 26 | 24 |
5 | 25 | 24 |
6 | 29 | 25 |
7 | 31 | 28 |
8 | 25 | 27 |
The test statistic is
Downtown Store | North Mall Store | |
Sample size | 25 | 20 |
Sample mean | $9 | $8 |
Sample standard deviation | $2 | $1 |
A 95% interval estimate for the difference between the two population means is
Store's Card | Major Credit Card | |
Sample size | 64 | 49 |
Sample mean | $140 | $125 |
Population standard deviation | $10 | $8 |
A point estimate for the difference between the mean purchases of all users of the two credit cards is
Product | Shoppers Surveyed | Shoppers Favoring This Product |
A | 800 | 560 |
B | 900 | 612 |
The 95% confidence interval estimate for the difference between the populations favoring the products is
The following table shows the predicted sales (in $1000s) and the actual sales (in $1000s) for six stores over a six-month period.
What is the mean of the matched samples data in the above table?
Store's Card | Major Credit Card | |
Sample size | 64 | 49 |
Sample mean | $140 | $125 |
Population standard deviation | $10 | $8 |
A 95% confidence interval estimate for the difference between the average purchases of all customers using the two different credit cards is
The daily production rates for a sample of workers before and after a training program are shown below. Assume the population of differences is normally distributed.
Worker | Before | After |
1 | 20 | 22 |
2 | 25 | 23 |
3 | 27 | 27 |
4 | 23 | 20 |
5 | 22 | 25 |
6 | 20 | 19 |
7 | 17 | 18 |
The point estimate for the difference between the means of the two populations is
Under Age of 18 | Over Age of 18 |
n1 = 500 | n2 = 600 |
Number of accidents = 180 | Number of accidents = 150 |
We are interested in determining if the accident proportions differ between the two age groups. The p-value is
Male | Female | |
Sample Size | 64 | 36 |
Sample Mean Salary (in $1000) | 44 | 41 |
Population Variance (σ2) | 128 | 72 |
At 95% confidence, the margin of error is
Driver | Manufacturer A | Manufacturer B |
1 | 32 | 28 |
2 | 27 | 22 |
3 | 26 | 27 |
4 | 26 | 24 |
5 | 25 | 24 |
6 | 29 | 25 |
7 | 31 | 28 |
8 | 25 | 27 |
The mean of the differences is
The daily production rates for a sample of workers before and after a training program are shown below. Assume the population of differences is normally distributed.
Worker | Before | After |
1 | 20 | 22 |
2 | 25 | 23 |
3 | 27 | 27 |
4 | 23 | 20 |
5 | 22 | 25 |
6 | 20 | 19 |
7 | 17 | 18 |
The null hypothesis to be tested is H0: μd = 0. The test statistic is
n = 49, x̄ = 50, s = 7
H0: μ ≥ 52
Ha: μ < 52
the test statistic is
Today | Five Years Ago | |
x̄ | 82 | 88 |
σ2 | 112.5 | 54 |
n | 45 | 36 |
What is the conclusion that can be reached about the difference in the average final examination scores between the two classes? (Use a .05 level of significance.)
Product | Shoppers Surveyed | Shoppers Favoring This Product |
A | 800 | 560 |
B | 900 | 612 |
The point estimate for the difference between the two population proportions in favor of this product is
Under Age of 18 | Over Age of 18 |
n1 = 500 | n2 = 600 |
Number of accidents = 180 | Number of accidents = 150 |
We are interested in determining if the accident proportions differ between the two age groups. The pooled estimator of the population proportion is
The daily production rates for a sample of workers before and after a training program are shown below. Assume the population of differences is normally distributed.
Worker | Before | After |
1 | 20 | 22 |
2 | 25 | 23 |
3 | 27 | 27 |
4 | 23 | 20 |
5 | 22 | 25 |
6 | 20 | 19 |
7 | 17 | 18 |
The point estimate for the difference between the means of the two populations is
Assume normally distributed populations with equal variances.
Sample 1 | Sample 2 | |
Sample Mean | 45 | 42 |
Sample Variance | 85 | 90 |
Sample Size | 10 | 12 |
The degrees of freedom for the t distribution are
Driver | Manufacturer A | Manufacturer B |
1 | 32 | 28 |
2 | 27 | 22 |
3 | 26 | 27 |
4 | 26 | 24 |
5 | 25 | 24 |
6 | 29 | 25 |
7 | 31 | 28 |
8 | 25 | 27 |
At α = .10, the null hypothesis
Today | Five Years Ago | |
x̄ | 82 | 88 |
σ2 | 112.5 | 54 |
n | 45 | 36 |
The test statistic for the difference between the two population means is
Under Age of 18 | Over Age of 18 |
n1 = 500 | n2 = 600 |
Number of accidents = 180 | Number of accidents = 150 |
We are interested in determining if the accident proportions differ between the two age groups. The p-value is
Today | Five Years Ago | |
x̄ | 82 | 88 |
σ2 | 112.5 | 54 |
n | 45 | 36 |
The p-value for the difference between the two population means is
Today | Five Years Ago | |
x̄ | 82 | 88 |
σ2 | 112.5 | 54 |
n | 45 | 36 |
The 95% confidence interval for the difference between the two population means is
Individual | Method 1 | Method 2 |
1 | 7 | 5 |
2 | 5 | 9 |
3 | 6 | 8 |
4 | 7 | 7 |
5 | 5 | 6 |
The 95% confidence interval for the difference between the two population means is
Today | Five Years Ago | |
x̄ | 82 | 88 |
σ2 | 112.5 | 54 |
n | 45 | 36 |
The point estimate for the difference between the means of the two populations is
Product | Shoppers Surveyed | Shoppers Favoring This Product |
A | 800 | 560 |
B | 900 | 612 |
The point estimate for the difference between the two population proportions in favor of this product is
Store's Card | Major Credit Card | |
Sample size | 64 | 49 |
Sample mean | $140 | $125 |
Population standard deviation | $10 | $8 |
At 95% confidence, the margin of error is
Store's Card | Major Credit Card | |
Sample size | 64 | 49 |
Sample mean | $140 | $125 |
Population standard deviation | $10 | $8 |
A point estimate for the difference between the mean purchases of all users of the two credit cards is
Product | Shoppers Surveyed | Shoppers Favoring This Product |
A | 800 | 560 |
B | 900 | 612 |
At 95% confidence, the margin of error is
Store's Card | Major Credit Card | |
Sample size | 64 | 49 |
Sample mean | $140 | $125 |
Population standard deviation | $10 | $8 |
A point estimate for the difference between the mean purchases of all users of the two credit cards is
Music Type | Teenagers Surveyed | Teenagers Favoring This Type |
Pop | 800 | 384 |
Rap | 900 | 450 |
The point estimate of the difference between the two population proportions is
Individual | Method 1 | Method 2 |
1 | 7 | 5 |
2 | 5 | 9 |
3 | 6 | 8 |
4 | 7 | 7 |
5 | 5 | 6 |
The 95% confidence interval for the difference between the two population means is
Under Age of 18 | Over Age of 18 |
n1 = 500 | n2 = 600 |
Number of accidents = 180 | Number of accidents = 150 |
We are interested in determining if the accident proportions differ between the two age groups. The pooled estimator of the population proportion is
Under Age of 18 | Over Age of 18 |
n1 = 500 | n2 = 600 |
Number of accidents = 180 | Number of accidents = 150 |
We are interested in determining if the accident proportions differ between the two age groups. The p-value is
The local cable company is interested in determining whether or not the proportion of subscribers has increased during the past year. A random sample of households selected last year is compared with a random sample of households selected this year. Results are summarized below.
What is the value of the pooled estimate of p?
Product | Shoppers Surveyed | Shoppers Favoring This Product |
A | 800 | 560 |
B | 900 | 612 |
The point estimate for the difference between the two population proportions in favor of this product is
Company A | Company B | |
Sample size | 80 | 60 |
Sample mean | $16.75 | $16.25 |
Population standard deviation | $1.00 | $.95 |
The test statistic is
The local cable company is interested in determining whether or not the proportion of subscribers has increased during the past year. A random sample of households selected last year is compared with a random sample of households selected this year. Results are summarized below.
What is the value of the pooled estimate of p?
Male | Female | |
Sample Size | 64 | 36 |
Sample Mean Salary (in $1000) | 44 | 41 |
Population Variance (σ2) | 128 | 72 |
If you are interested in testing whether or not the population average salary of males is significantly greater than that of females, the test statistic is
Product | Shoppers Surveyed | Shoppers Favoring This Product |
A | 800 | 560 |
B | 900 | 612 |
The standard error of p̄1 - p̄2 is
Downtown Store | North Mall Store | |
Sample size | 25 | 20 |
Sample mean | $9 | $8 |
Sample standard deviation | $2 | $1 |
A 95% interval estimate for the difference between the two population means is
Assume normally distributed populations with equal variances.
Sample 1 | Sample 2 | |
Sample Mean | 45 | 42 |
Sample Variance | 85 | 90 |
Sample Size | 10 | 12 |
The point estimate for the difference between the means of the two populations is
Male | Female | |
Sample Size | 64 | 36 |
Sample Mean Salary (in $1000) | 44 | 41 |
Population Variance (σ2) | 128 | 72 |
The 95% confidence interval for the difference between the means of the two populations is
Assume normally distributed populations with equal variances.
Sample 1 | Sample 2 | |
Sample Mean | 45 | 42 |
Sample Variance | 85 | 90 |
Sample Size | 10 | 12 |
The degrees of freedom for the t distribution are
Assume normally distributed populations with equal variances.
Sample 1 | Sample 2 | |
Sample Mean | 45 | 42 |
Sample Variance | 85 | 90 |
Sample Size | 10 | 12 |
The 95% confidence interval for the difference between the two population means is (use rounded standard error)
Downtown Store | North Mall Store | |
Sample size | 25 | 20 |
Sample mean | $9 | $8 |
Sample standard deviation | $2 | $1 |
A point estimate for the difference between the two population means is
H0: p ≤ .20
Ha: p > .20
the test statistic is
Music Type | Teenagers Surveyed | Teenagers Favoring This Type |
Pop | 800 | 384 |
Rap | 900 | 450 |
The 95% confidence interval for the difference between the two population proportions is
The daily production rates for a sample of workers before and after a training program are shown below. Assume the population of differences is normally distributed.
Worker | Before | After |
1 | 20 | 22 |
2 | 25 | 23 |
3 | 27 | 27 |
4 | 23 | 20 |
5 | 22 | 25 |
6 | 20 | 19 |
7 | 17 | 18 |
The null hypothesis to be tested is H0: μd = 0. The test statistic is
Production output (i.e., number of parts) for a random sample of days from two different plants is shown below.
What is the estimate of the standard deviation for the difference between the two means?
The following information was obtained from independent random samples. Suppose we are interested in testing H0: µ1 – µ2 = 15 and Ha: µ1 – µ2 ≠ 15.
What is the test statistic used in the hypothesis test for the difference between the two population means?
Today | Five Years Ago | |
x̄ | 82 | 88 |
σ2 | 112.5 | 54 |
n | 45 | 36 |
The standard error of x̄1 - x̄2 is
Individual | Method 1 | Method 2 |
1 | 7 | 5 |
2 | 5 | 9 |
3 | 6 | 8 |
4 | 7 | 7 |
5 | 5 | 6 |
The 95% confidence interval for the difference between the two population means is
H0: p ≤ .20
Ha: p > .20
the test statistic is
Today | Five Years Ago | |
x̄ | 82 | 88 |
σ2 | 112.5 | 54 |
n | 45 | 36 |
The standard error of x̄1 - x̄2 is
Store's Card | Major Credit Card | |
Sample size | 64 | 49 |
Sample mean | $140 | $125 |
Population standard deviation | $10 | $8 |
At 95% confidence, the margin of error is
The following information was obtained from independent random samples. Suppose we are interested in testing H0: µ1 – µ2 = 15 and Ha: µ1 – µ2 ≠ 15.
What is the test statistic used in the hypothesis test for the difference between the two population means?
Assume normally distributed populations with equal variances.
Sample 1 | Sample 2 | |
Sample Mean | 45 | 42 |
Sample Variance | 85 | 90 |
Sample Size | 10 | 12 |
The degrees of freedom for the t distribution are
Assume normally distributed populations with equal variances.
Sample 1 | Sample 2 | |
Sample Mean | 45 | 42 |
Sample Variance | 85 | 90 |
Sample Size | 10 | 12 |
The degrees of freedom for the t distribution are
Individual | Method 1 | Method 2 |
1 | 7 | 5 |
2 | 5 | 9 |
3 | 6 | 8 |
4 | 7 | 7 |
5 | 5 | 6 |
If the null hypothesis H0: μd = 0 is tested at the 5% level,
Male | Female | |
Sample Size | 64 | 36 |
Sample Mean Salary (in $1000) | 44 | 41 |
Population Variance (σ2) | 128 | 72 |
The standard error of the difference between the two sample means is
The following information was obtained from matched samples:
If the null hypothesis tested is H0: µd = 0, what is the test statistic for the difference between the two population means?
Driver | Manufacturer A | Manufacturer B |
1 | 32 | 28 |
2 | 27 | 22 |
3 | 26 | 27 |
4 | 26 | 24 |
5 | 25 | 24 |
6 | 29 | 25 |
7 | 31 | 28 |
8 | 25 | 27 |
The test statistic is
Two independent types of a product were produced. The dollar amount of sales for each type over a one-month period was recorded. Assume the sales values are normally distributed. The results are given in the table below.
What are the p-value and conclusion for the hypothesis test of H0: µ1 – µ2 = 0 vs. Ha: µ1 – µ2 < 0 using α = 0.05?
Under Age of 18 | Over Age of 18 |
n1 = 500 | n2 = 600 |
Number of accidents = 180 | Number of accidents = 150 |
We are interested in determining if the accident proportions differ between the two age groups. The p-value is
Driver | Manufacturer A | Manufacturer B |
1 | 32 | 28 |
2 | 27 | 22 |
3 | 26 | 27 |
4 | 26 | 24 |
5 | 25 | 24 |
6 | 29 | 25 |
7 | 31 | 28 |
8 | 25 | 27 |
The mean of the differences is
Driver | Manufacturer A | Manufacturer B |
1 | 32 | 28 |
2 | 27 | 22 |
3 | 26 | 27 |
4 | 26 | 24 |
5 | 25 | 24 |
6 | 29 | 25 |
7 | 31 | 28 |
8 | 25 | 27 |
The mean of the differences is
Production output (i.e., number of parts) for a random sample of days from two different plants is shown below.
What is the estimate of the standard deviation for the difference between the two means?
Product | Shoppers Surveyed | Shoppers Favoring This Product |
A | 800 | 560 |
B | 900 | 612 |
The point estimate for the difference between the two population proportions in favor of this product is
Under Age of 18 | Over Age of 18 |
n1 = 500 | n2 = 600 |
Number of accidents = 180 | Number of accidents = 150 |
We are interested in determining if the accident proportions differ between the two age groups. The p-value is
Assume normally distributed populations with equal variances.
Sample 1 | Sample 2 | |
Sample Mean | 45 | 42 |
Sample Variance | 85 | 90 |
Sample Size | 10 | 12 |
The 95% confidence interval for the difference between the two population means is (use rounded standard error)
Male | Female | |
Sample Size | 64 | 36 |
Sample Mean Salary (in $1000) | 44 | 41 |
Population Variance (σ2) | 128 | 72 |
The standard error of the difference between the two sample means is
Male | Female | |
Sample Size | 64 | 36 |
Sample Mean Salary (in $1000) | 44 | 41 |
Population Variance (σ2) | 128 | 72 |
The standard error of the difference between the two sample means is
A simple random sample of 64 observations was taken from a large population. The sample mean and the standard deviation were determined to be 320 and 120 respectively. The standard error of the mean is
16 | 19 | 18 | 17 | 20 | 18 |
The point estimate of the mean of the population is


10 | 8 | 11 | 11 |
The 95% confidence interval for μ is
12 | 18 | 19 | 20 | 21 |
A point estimate of the mean is
16 | 19 | 18 | 17 | 20 | 18 |
The point estimate of the population standard deviation is
10 | 8 | 11 | 11 |
The 95% confidence interval for μ is
16 | 19 | 18 | 17 | 20 | 18 |
The point estimate of the population standard deviation is
16 | 19 | 18 | 17 | 20 | 18 |
The point estimate of the population standard deviation is
13 | 15 | 14 | 16 | 12 |
If the population consisted of 10 elements, how many different random samples of size 6 could be drawn from the population?


13 | 15 | 14 | 16 | 12 |
If the population consisted of 10 elements, how many different random samples of size 6 could be drawn from the population?
Given the sampling distribution of the sample mean shown here, which of the following values is a reasonable estimate for the population mean?
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